# Given that the length of a parallelogram is (x^2-5x) and the width is (2x^2+x+3), how do you find the area of the figure in terms of x?

$\left({x}^{2} - 5 x\right) \left(2 {x}^{2} + x + 3\right)$
$= \left({x}^{2} - 5 x\right) \left(2 {x}^{2} + x + 3\right)$