Given the acceleration as (3t^2+2)i+6e^(-2t) j+10cos 5tk, find the magnitude of velocity at t=0?
2 Answers
No initial points?
Explanation:
given that
and we have
so
Notice that
we can find the velocity in vectors by integrating the value of acceleration
i.e. vu
Explanation:
(Given) a=
so,
=
=
now, for finding velocity put value of t=0.
=
=
=