Given the balanced equation, #LiOH + KCl -> LiCl + KOH#, what is the theoretical yield of lithium chloride if you start this reaction with 20.0 grams of lithium hydroxide?

1 Answer
Mar 26, 2016

Answer:

The theoretical yield is #"35.4 g LiCl"#.

Explanation:

The five basic steps to solve a theoretical yield problem are:

  1. Write the balanced equation for the reaction between #"LiOH"# and #"KCl"#.
  2. Use the molar mass of #"LiOH"# to convert grams of #"LiOH"# to moles of #"LiOH"#.
  3. Use the molar ratio from the balanced equation to convert moles of #"LiOH"# to moles of #"LiCl"#.
  4. Use the molar mass of #"LiCl"# to convert moles of #"LiCl"# to grams of #"LiCl"#.

In summary, the conversions are

#"g LiOH" stackrel(color(blue)("molar mass"color(white)(m)))(→) "mol LiOH" stackrel(color(blue)("molar ratio"color(white)(m)))(→) "mol LiCl" stackrel(color(blue)("molar mass"color(white)(m)))(→) "g LiCl"#

To 3 significant figures, you should get

#"20.0 g LiOH" → "0.835 mol LiOH" → "0.835 mol LiCl" → "35.4 g LiCl"#