# Given the balanced equation, LiOH + KCl -> LiCl + KOH, what is the theoretical yield of lithium chloride if you start this reaction with 20.0 grams of lithium hydroxide?

Mar 26, 2016

The theoretical yield is $\text{35.4 g LiCl}$.

#### Explanation:

The five basic steps to solve a theoretical yield problem are:

1. Write the balanced equation for the reaction between $\text{LiOH}$ and $\text{KCl}$.
2. Use the molar mass of $\text{LiOH}$ to convert grams of $\text{LiOH}$ to moles of $\text{LiOH}$.
3. Use the molar ratio from the balanced equation to convert moles of $\text{LiOH}$ to moles of $\text{LiCl}$.
4. Use the molar mass of $\text{LiCl}$ to convert moles of $\text{LiCl}$ to grams of $\text{LiCl}$.

In summary, the conversions are

$\text{g LiOH" stackrel(color(blue)("molar mass"color(white)(m)))(→) "mol LiOH" stackrel(color(blue)("molar ratio"color(white)(m)))(→) "mol LiCl" stackrel(color(blue)("molar mass"color(white)(m)))(→) "g LiCl}$

To 3 significant figures, you should get

$\text{20.0 g LiOH" → "0.835 mol LiOH" → "0.835 mol LiCl" → "35.4 g LiCl}$