# Given the balanced equation representing a reaction: 2CO(g) + O_2(g) -> 2CO_2(g). What is the mole ratio of CO(g) to CO_2(g) in this reaction?

May 20, 2018

Is it not $1 : 1$...?

#### Explanation:

We could write...$C O \left(g\right) + \frac{1}{2} {O}_{2} \rightarrow C {O}_{2} \left(g\right)$, instead of ...

$2 C O \left(g\right) + {O}_{2} \rightarrow 2 C {O}_{2} \left(g\right)$

In either scenario both mass and charge are balanced, as required for a stoichiometric equation...and this is why teachers go to such great efforts to teach stoichiometry....and we could put in numbers to stress the mass balance of the equation....

${\underbrace{C O \left(g\right) + \frac{1}{2} {O}_{2}}}_{\text{28 g + 16 g = 44 g" rarr underbrace(CO_2(g))_"44 g}}$