Given the balanced equation representing the reaction between methane and oxygen: #CH_4 + 2O_2 -> CO_2 + 2H_2O#. According to this equation, what is the mole ratio of oxygen to methane?

1 Answer
Mar 4, 2017

Answer:

You have a stoichiometrically balanced equation that represents methane combustion. Should you not tell us?

Explanation:

#CH_4(g) + 2O_2(g) rarr CO_2(g) + 2H_2O(l)#

The equation explicitly tells us that one equivalent of methane gas reacts with two equiv of dioxygen to give one equiv of carbon dioxide, and two equiv of water. So we start with #16*g# methane gas, and this reacts with #64*g# dioxygen gas. You tell us the molar ratio.