# Given the following, what would the new volume of the balloon be?

## A child has a toy balloon with a volume of 1.80 liters. The temperature of the balloon when it was filled was 20° C and the pressure was 1.00 atm. If the child were to let go of the balloon and it rose 3 km into the sky where the pressure is 0.667 atm and the temperature is -10° C.....

Sep 9, 2016

${V}_{2} \cong 2.5 \cdot L$

#### Explanation:

The combined gas equation holds that for constant $n$:

$\frac{{P}_{1} {V}_{1}}{T} _ 1 = \frac{{P}_{2} {V}_{2}}{T} _ 2$

Thus ${V}_{2}$ $=$ $\frac{{P}_{1} \times {T}_{2} \times {V}_{1}}{{P}_{2} \times {T}_{1}}$ (this clearly has the units of volume.)

$=$ $\frac{1 \cdot a t m \times 263 \cdot K \times 1.80 \cdot L}{0.667 \cdot a t m \times 293 \cdot K}$ $=$ ??L