Given the graph of #y=x^2+3x-5#, how do you draw a line to solve #x^2+2x-2=0#?

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Answer 1 · 2017-11-25T12:08:41

#x=0.7321#and #x=-2.7321#

First, express the equation #x^2+2x-2=0# in terms of #x^2#

#x^2+2x-2=0#

#x^2=-2x+2#

Then, insert this equation into #y=x^2+3x-5#

#y=-2x+2+3x-5#

#y=x-3#

Next, draw this line on the graph on the same axes as the equation #y=x^2+3x-5#

The intersection points of these two graphs is the solution of the equations, that is #x=0.7321#and #x=-2.7321# or close to it.