Given the values #(7,1.395),(8,1.442),(9,1.482),(10,1.517),(11,1.549),(12,1.576), (13,1.602)#, without constructing interpolation polynomial, how do I estimate the value of the function when #x=8.5# ?

1 Answer
Mar 14, 2018

#1.463#

Explanation:

Given:

#((7,1.395),(8,1.442),(9,1.482),(10,1.517),(11,1.549),(12,1.576), (13,1.602))#

Notice the #x# values are equally spaced, so we can get some information using a method of differences:

Write down the initial sequence of #y# values:

#1.395, 1.442, 1.482, 1.517, 1.549, 1.576, 1.602#

Write down the sequence of differences between successive terms:

#0.047, 0.040, 0.035, 0.032, 0.027, 0.026#

Note that these are monotonically decreasing.

Let's split each roughly in half, but making the first half slightly larger to get:

#0.024, 0.023, 0.021, 0.019, 0.018, 0.017, 0.016, 0.016, 0.014, 0.013, 0.013, 0.013#

That looks like it is decreasing reasonably smoothly.

Now apply these half differences to the previous sequence in order to interpolate:

#1.395, 1.419, 1.442, color(red)(1.463), 1.482, 1.500, 1.517, 1.533, 1.549, 1.563, 1.576, 1.589, 1.602#

So the approximation for #f(8.5)# is #1.463#