Given this; #P(x)=x^3-7x^2-7x+1#, how do I find the function values of the following? (1) #P(-1)# (2) #P(5)# (3) #P(-5)#

1 Answer
Jim G.
Jul 22, 2018

#0,-84,-264#

Explanation:

#"substitute the given values for x into "P(x)#

#P(color(red)(-1))=(color(red)(-1))^3-7(color(red)(-1))^2-7(color(red)(-1))+1#

#color(white)(xxxxx)=-1-7+7+1=0#

#P(color(red)(5))=(color(red)(5))^3-7(color(red)(5))^2-7(color(red)(5))+1#

#color(white)(xxx)=125-175-35+1=-84#

#P(color(red)(-5))=(color(red)(-5))^3-7(color(red)(-5))^2-7(color(red)(-5))+1#

#color(white)(xxxxx)=-125-175+35+1=-264#

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