Given #x^5# if x<0 and 2x + 1 if x >= 0, how do you find f(0)?

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Answer 1 · 2016-08-07T13:17:12

#=>f(0)=0+1 = 1#

I think they call this a 'stepwise solution'

#f(0)# means that you assign the value of 0 to #x#

Condition 1: if #x<0# then you apply the calculation #x^5#

Condition 2: if #x>=0# then you apply the calculation #2x+1#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
We are given the value of #x# as 0

Condition 1 is that #x# must be less than 0 so as #x=0# this equation does not apply.

Condition 2 is that #x# can be 0 or grater than 0. So as #x=0# this equation is the one we use.

#=>f(0)->2x+1#

#=>f(0)=2(0)+1#

#=>f(0)=0+1 = 1#