# Given f(x)=x^5" if "x<0 and f(x)=2x + 1" if "x >= 0, how do you find f(1)?

$f \left(1\right) = 3$
$\textcolor{red}{x = 1} \implies x \ge 0$ so we use $f \left(x\right) = 2 x + 1$
$f \left(x\right) = 2 \left(\textcolor{red}{1}\right) + 1 = 3$