Glucose is an important sugar in many biochemical reactions. What is the molarity of a solution that contains 500 grams of glucose (Molecular weight 180.16 g/mol) in 0.72 liters of solution?

Under $3 \cdot m o l \cdot {L}^{-} 1$.
$\text{Concentration}$ $=$ $\text{Moles of solute (moles)"/"Volume of solution (Litres)}$
Here, $\frac{500 \cdot \cancel{g}}{0.72 \cdot L} \times \frac{1}{180.16 \cdot \cancel{g} \cdot m o {l}^{-} 1}$ $=$ ??mol*L^-1