#H_2(g) + 2NO(g) -> H_20(g) + N_2O(g)#. At high temperatures, doubling the concentration of #H_2# doubles the rate of reaction, while doubling the concentration of #NO# increases the rate fourfold. How do you write a rate law for this reaction?
And we write the overall rate law.....
Note that this conveniently follows the stoichiometric equation given; it did not NECESSARILY have to follow this rate law.