H = [(x+2y)/z^2]ay + (2/z)az How about curl. (curl H = ?)

1 Answer
Ultrilliam
May 5, 2018

#"curl " bb H =(2x+4y)/z^3 bb(a_x) + 1/z^2 bb(a_z)#

Explanation:

#bb H = (0 bb a_x +) (x+2y)/z^2 bb(a_y) + 2/z bb(a_z)#

#bb nabla times bb H = det ((bb(a_x), bb(a_y), bb(a_z)),(partial_x, partial_y, partial_z),(0, (x+2y)/z^2, 2/z))#

#=(0 + 2 (x+2y)/z^3 ) bb(a_x) -(0 - 0) bb(a_y) + (1/z^2 - 0 ) bb(a_z)#

#=(2x+4y)/z^3 bb(a_x) + 1/z^2 bb(a_z)#

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