Hardy-Weinburg Equlibrium?

If a population that is in Hardy-Weinburg equilibrium has 500 individuals, with allele frequencies for p and q of 0.55 and 0.45, respectively, and 30% of the heterozygotes are killed by a natural disaster, how many heterozygotes are left? Will the population stay in genetic equilibrium?

If a population that is in Hardy-Weinburg equilibrium has 500 individuals, with allele frequencies for p and q of 0.55 and 0.45, respectively, and 30% of the heterozygotes are killed by a natural disaster, how many heterozygotes are left? Will the population stay in genetic equilibrium?

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Mar 1, 2018

Answer:

Heterozygotes left: #0.346# or #0.3465# (depending on if you need to round.)
Genetic Equilibrium: No

Explanation:

Population: #500# individuals

  • #p = 0.55#
  • #q = 0.45#

To find the heterozygotes of the individual, you have to multiply.

#2pq = 2 xx (0.55) xx (0.45) = 0.495#

Now, #30%# of #0.495#

#0.495 xx .30 = 0.1485#

Heterozygotes left:

#0.495 - 0.1485 = 0.3465#

or the rounded answer...

#0.495 - 0.149 = 0.346#

For genetic equilibrium to occur p and q must equal each other without any factors of mutation, random mating, migration, genetic drift, or for a species to have an infinitely large population.

For this problem, since some of the species died off; No, this species will not stay in genetic equilibrium.

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