If the train travels #150# miles in #2 1/2# hours
then we have a distance to time ratio of
#color(white)("XXX")150" miles":2 1/2" hours"#
which can also be expressed as a fraction:
#color(white)("XXX")(150" miles")/(2 1/2" hours")#
Simplifying:
#color(white)("XXX")(150" miles")/(2 1/2" hours")xx2/2=(300" miles")/(5" hours")=(60" miles")/("hour")#
In #2# hours, traveling at #60 "miles/hour"# the train would travel
#color(white)("XXX")(60" miles")/(cancel("hour"))xx(2 cancel(" hours"))/color(white)(x)=120" miles"#
Similarly
In #3# hours, traveling at #60 "miles/hour"# the train would travel
#color(white)("XXX")(60" miles")/(cancel("hour"))xx(3 cancel(" hours"))/color(white)(x)=180" miles"#
and
In #7# hours, traveling at #60 "miles/hour"# the train would travel
#color(white)("XXX")(60" miles")/(cancel("hour"))xx(7 cancel(" hours"))/color(white)(x)=420" miles"#
