Height attained by particle in vertical direction changing with time y= 5t-5t^2 then maximum height attained by particle is?

1 Answer
Mar 12, 2017

The maximum height is =1.25m

Explanation:

We determine the first and second derivatives

y=5t-5t^2

dy/dt=5-10t

dy/dt=0 when 5-10t=0

That is,

5=10t

t=1/2

(d^2y)/dt^2=-10

As, (d^2y)/dt^2<0, this is a maximum

y(2)=5*1/2-5*1/4=5/4=1.25m

graph{5x-5x^2 [-3.442, 3.486, -0.016, 3.448]}