Hello friends, please, I need to know how to get the answer out of this exponential equation?

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1 Answer
May 14, 2018

Answer:

#x=3/4#

Explanation:

We have

#49^x=7sqrt7#

Knowing that #49=7^2# and #sqrt7=7^(1/2)#, we get

#7^(2x)=7*7^(1/2)#

Using the property that #alpha^a*alpha^b=alpha^(a+b)#:

#7^color(red)(2x)=7^color(red)(3/2)#

Since we have #7# as the base of the exponential function on both sides, let us take the #log_7# of both:

#2x=3/2=>x=3/4#