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Answer 1 · 2017-07-30T18:50:59

The solutions are, #a!=4#, #b=-1# and #c=-12#

The vertical asymptotes are #x=4# and #x=-3#

Therefore,

The denominator is

#=(x-4)(x+3)=x^2-4x+3x-12=x^2-x-12#

But the denominator is

#x^2+bx+c=x^2-x-12#

So,

#b=-1#

#c=-12#

The function is #y=(x-a)/(x^2+bx+c)=(x-a)/((x-4)(x+3))#

The restriction is #x-a!=x-4#

#a!=4#