Help me to prove that $tan^2A + cot^2 A + 2 = sec^2 A. csc^2 A$ please? Thank you before.

Question

$tan^2A + cot^2 A + 2 = sec^2 A. csc^2 A$

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Answer 1 · 2017-08-26T06:26:48

$LHS=tan^2A+cot^2A+2$

$=tan^2A+1+cot^2A+1$

$=sec^2A+csc^2A$

$=1/cos^2A+1/sin^2A$

$=(sin^2A+cos^2A)/(cos^2Asin^2A)$

$=1/(cos^2Asin^2A)$

$=sec^2Acsc^2A=RHS$