Question

Help with [part c and d please?

Answer 1

The dollar has the trajectory of a parabola from the equation that I see. You have to set `s=0` and solve for its roots. That will determine when the dollar is at ground level.

`-16t^2+555=0`

`-16t^2=-555`

`t^2=(-555)/-16=34.6875`

`t=sqrt34.6875=5.89`

After `5.89` seconds, the dollar will hit the ground.

Velocity function is the derivative of the position function `s`:

`(ds)/dt=v=-32t`

The velocity at `5.89` seconds is:

`v=-32(5.89)=-188.48` feet per second