Help with precalculus/ trig homework?!

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Answer 1 · 2018-03-03T03:20:12

#cos2theta=#
#cos^2theta-sin^2theta=#
#(-1/2)^2-(sqrt 3/ 2)^2=#
#1/4-3/4=#
#-2/4=#
#-1/2=#
#-.500#