Here is the chemical reaction - Ca(NO3)2 + (NH4)3PO4 --> Double displacement follows... If you start with 10.25 mL of .553M Ca(NO3)2 soln, how many moles of calcium nitrate do you have in the soln? Also a part 2 in the question.

1 Answer
Jan 18, 2018

We got #5.67xx10^-3*mol# with respect to calcium nitrate,,,

Explanation:

Bt definition...#"Concentration"="Moles of solute"/"Volume of solution"#

And thus #"moles of solute"="concentration"xx"volume"#

#=10.25xx10^-3*Lxx0.553*mol*L^-1=??*mol#

Note that this molar quantity of calcium biphosphate would precipitate from this solution.....

#Ca^(2+) + HPO_4^(2-) rarr CaHPO_4(s)darr#