Hi there! Can you take a few minutes to help me out please? Thank you!

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1 Answer
Sep 26, 2017

b=4sqrt22 units,
angleA=9.1^@
angleB=80.9^@

Explanation:

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Given that DeltaABC is right-angled at C, => AB is the hypotenuse, as shown in the figure.
By Pythagorean theorem,
c^2=a^2+b^2,
=> b^2=c^2-a^2
=> b=sqrt(c^2-a^2)=sqrt(19^2-3^2)=sqrt352=sqrt(16xx22)=4sqrt22
=> b=4sqrt22~~18.8 units

SinangleA=(BC)/(AB)=a/c=3/19
=> angleA=sin^-1(3/19)=9.08^@=9.1^@ (to the nearest tenth)

=> angleB=90-9.1=80.9^@