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Question

#int_0^1-10^4cos(2x)e^-2dx##int_0^2dz#

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Answer 1 · 2018-04-28T08:58:16

the answer #-10^4*e^-2*[sin(2)]#

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#int_0^1-10^4cos(2x)e^-2dx=-10^4*e^-2int_0^1cos(2x)*dx=#

#-10^4*e^-2*1/2int_0^1(2cos(2x))*dx#

#-10^4*e^-2*1/2[sin(2x)]_0^1=-10^4*e^-2*1/2[sin(2)]#

#int_0^2dz=[z]_0^2=2#

#int_0^1-10^4cos(2x)e^-2dx*int_0^2dz=-10^4*e^-2*1/2[sin(2)]*2 =-10^4*e^-2*[sin(2)]#