How are microstates formed in chemistry?

1 Answer
Aug 7, 2017

Automatically?

Macrostates can be observed, even with quantum-sized particles, and one can extract microstates consistent with those macrostates simply by specifying the macrostate and using statistical predictions to enumerate the microstates.


A microstate is one state (of many) for an ensemble of particles that is present in a distribution of possible configurations of a system, that all collectively describe a macrostate.

So, let's say a macrostate was described by the following statement:

Two particles placed in a four-compartment box, such that neither particle is in the same compartment.

Then, if the compartments are distinguishable, and the particles are distinguishable, there are #bb12# possible microstates:

#barul|" "cdot" "|barul|" "color(white)(cdot)" "|" "bb((1))#
#ul|" "cdot" "|ul|" "color(white)(cdot)" "|#
#(+1" for particle exchange")#

#barul|" "cdot" "|barul|" "cdot" "|" "bb((2))#
#ul|" "color(white)(cdot)" "|ul|" "color(white)(cdot)" "|#
#(+1" for particle exchange")#

#barul|" "color(white)(cdot)" "|barul|" "cdot" "|" "bb((3))#
#ul|" "color(white)(cdot)" "|ul|" "cdot" "|#
#(+1" for particle exchange")#

#barul|" "color(white)(cdot)" "|barul|" "color(white)(cdot)" "|" "bb((4))#
#ul|" "cdot" "|ul|" "cdot" "|#
#(+1" for particle exchange")#

#barul|" "color(white)(cdot)" "|barul|" "cdot" "|" "bb((5))#
#ul|" "cdot" "|ul|" "color(white)(cdot)" "|#
#(+1" for particle exchange")#

#barul|" "cdot" "|barul|" "color(white)(cdot)" "|" "bb((6))#
#ul|" "color(white)(cdot)" "|ul|" "cdot" "|#
#(+1" for particle exchange")#

If the particles are indistinguishable, then we have an extra (redundant) microstate which would be due to their exchange, and we only have #bb6# microstates possible here.

Each one would be a linear combination #psi_i# of the identical-looking configuration pairs #(phi_(ia),phi_(ib))#:

#psi_1 = c_1phi_(1a) + c_2phi_(1b)#
#psi_2 = c_3phi_(2a) + c_4phi_(2b)#
#psi_3 = c_5phi_(3a) + c_6phi_(3b)#
#psi_4 = c_7phi_(4a) + c_8phi_(4b)#
#psi_5 = c_9phi_(5a) + c_10phi_(5b)#
#psi_6 = c_11phi_(6a) + c_12phi_(6b)#

where the coefficients #c_i# describe the contribution the state makes to the distribution given by #psi_i#.

If the compartments are ALSO indistinguishable (but the boxes, stay connected in seemingly the same way), then...

  • configurations #(1)#, #(2)#, #(3)#, and #(4)# (meaning #psi_1, psi_2, psi_3, psi_4#) are duplicates of each other (accounting for #90^@# and #180^@# rotational permutations, keeping the compartments sitting in the same orientation).
  • configurations #(5)# and #(6)# (meaning #psi_5, psi_6#) are duplicates of each other (accounting for #90^@# rotational permutations, keeping the compartments sitting in the same orientation).

As a result, with indistinguishable compartments AND particles, we only have #bb2# nonredundant microstates #Psi_i# consistent with the given macrostate:

#Psi_A = c_13psi_1 + c_14psi_2 + c_15 psi_3 + c_16 psi_4#

(particles in adjacent compartments)

#Psi_B = c_17 psi_5 + c_18 psi_6#

(particles in diagonal compartments)

Examples of other complications might be:

  1. The particles (presumed indistinguishable) that occupy the same compartment at the same time must be of opposite spin (fermions, such as electrons), restricting us to #bb"two"# particles maximum per compartment.
  2. #bb"Any number"# of particles (presumed indistinguishable) could occupy the same compartment at the same time (bosons, such as photons).