# How are mole ratios derived from balance equations?

May 12, 2017

$C {H}_{4} \left(g\right) + 2 {O}_{2} \left(g\right) \rightarrow C {O}_{2} \left(g\right) + 2 {H}_{2} O \left(g\right) + \Delta$
The mole ration simply follows the ratio of the stoichiometric coefficients: $1 : 2 : 1 : 2$, i.e. $16 \cdot g$ methane is oxidized by $64 \cdot g$ of dioxygen to $44 \cdot g$ of carbon, and $36 \cdot g$ of water. Mass and charge are balanced.....................