How can (125a^15b^7/-8a^3b^4)^(4/3) be simplified?

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Answer 1 · 2018-07-13T10:22:48

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#((125a^15 b^7)/(-8b^4))^(4/3)#

Answer 2 · 2018-07-13T13:30:02

#(625a^16b^4)/16#

#((125a^15b^7)/(-8a^3b^4))^(4/3)#

#:.=(5^3a^15b^7)/(-2^3a^3b^4)#

#:.=(5^4a^20b^(28/3))/(-2^4a^4b^(16/3))#

#:.=(5^4a^(20-4)b^(28/3-16/3))/(-2^4)#

#:.=(625a^16b^(12/3))/(16)#

#:.=(625a^16b^4)/(16)#