How can i Calculate the mass of oxygen in 350 g of Al(C2H3O2)3?

1 Answer
anor277
May 10, 2018

Well, what is your molar quantity of #"aluminum acetate"#?

Explanation:

You gots....#(350*g)/(204.11 *g·mol^-1)=1.72*mol#

And given #"Al(O(O=)CCH"_3")"_3#....CLEARLY there are SIX moles of oxygen per mole of aluminum salt.

And so we got #10.3*mol*"oxygen"# in this quantity...

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