# How can I draw the Lewis structure for PH3?

Jul 16, 2014

Phosphosus has an electron configuration of $\left[N e\right] 2 {s}^{2} 2 {p}^{3}$.
Therefore, it has a dot digram in the red of two electrons on top and one electron on each side. Providing for three open bonding sites.

Hydrogen has an electron configuration of $1 {s}^{1}$. Therefore, it has only one electron on top. Each of the three hydrogens will fill one of the empty spaces of the phosphorus atom in a covalent bond. This will provide eight electrons for phosphorus, to complete the rule of octet.

Each hydrogen now has two electrons to complete the rule of duet.