# How can I find c and d if 8 cos (theta - pi / 3)=c sin theta + d cos theta?

$\cos \left(a - \frac{\pi}{3}\right) = \cos a . \cos \left(\frac{\pi}{3}\right) + \sin a . \sin \frac{\pi}{3} =$
$= \left(\frac{1}{2}\right) \cos a + \left(\frac{\sqrt{3}}{2}\right) \sin a$ = $\left(\frac{\sqrt{3}}{2}\right) \sin a + \left(\frac{1}{2}\right) \cos a$
$8 \cos \left(a - \frac{\pi}{3}\right) = 4 \sqrt{3} \sin a + 4 \cos a$
Answers::$c = 4 \sqrt{3} \mathmr{and} d = 4$