Question

How can I find the derivative of `y=c^x` using first principles, where c is an integer?

Answer 1

By rewriting a bit,

`y=c^x=e^{(lnc)x}`.

By Chain Rule,

`y'=e^{(lnc)x}cdot(lnc)=(lnc)c^x`

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I hope that this was helpful.