How can I find the domain of #f(x)=x/(sqrt(1-root(3)(1-x^2))#?

1 Answer
Guillaume L.
May 9, 2018

#D_"f":x in RR^"*"#

Explanation:

#x/sqrt(1-root(3)(1-x²))#
#1-root(3)(1-x²)>0#, because you can't divide by 0, and you can't have a square root of a negative number in #RR#.
#1-root(3)(1-x²)>0#
#1>root(3)(1-x²)#
#1>1-x²#
#x²>0#
#x in RR^"*"#
\0/ here's our answer!

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