# How can I find the first 5 numbers of a the sequence knowing that A(n)= 1 and A(n+1)= 4A(n)-2 ?

## Sorry if the formulas aren't very clear but everything that is between parentheses is supposed to be in subscript but I can't seem to find how to do it on this website. Thank you in advance

Jul 30, 2018

Below

#### Explanation:

${A}_{n} = 1$
${A}_{n + 1} = 4 {A}_{n} - 2$

Therefore, if you want the first 5 numbers, then you want to find ${A}_{1} , {A}_{2} , {A}_{3} , {A}_{4} \text{and} {A}_{5}$

${A}_{1} = 1$

${A}_{2} = 4 {A}_{1} - 2$
${A}_{2} = 4 \times 1 - 2$
${A}_{2} = 2$

${A}_{3} = 4 {A}_{2} - 2$
${A}_{3} = 4 \times 2 - 2$
${A}_{3} = 6$

${A}_{4} = 4 {A}_{3} - 2$
${A}_{4} = 4 \times 6 - 2$
${A}_{4} = 22$

${A}_{5} = 4 {A}_{4} - 2$
${A}_{5} = 4 \times 22 - 2$
${A}_{5} = 86$