Question

How can I solve, `2x^2+6x+2=0` by completing the square?

Answer 1

`x_1=(-3-sqrt(5))/2 or x_2=(-3+sqrt(5))/2`

Explanation:

`2x^2+6x+2=0|:2`
`x^2+3x+1=0`
`(x+3/2)^2-9/4+1=0|+5/4`
`x+3/2=+-sqrt(5)/2|-3/2`
`x=(-3+-sqrt(5))/2`
`x_1=(-3-sqrt(5))/2 or x_2=(-3+sqrt(5))/2`