How can I solve, $2x^2+6x+2=0$ by completing the square?

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Answer 1 · 2018-07-09T14:05:13

$x_1=(-3-sqrt(5))/2 or x_2=(-3+sqrt(5))/2$

$2x^2+6x+2=0|:2$
$x^2+3x+1=0$
$(x+3/2)^2-9/4+1=0|+5/4$
$x+3/2=+-sqrt(5)/2|-3/2$
$x=(-3+-sqrt(5))/2$
$x_1=(-3-sqrt(5))/2 or x_2=(-3+sqrt(5))/2$

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