Question

How can I solve this?

`2sin^2x - 1 =0`

Answer 1

`x = 45°` and `x = -45°`

Explanation:

Solve for `x`
`2sin^2x - 1 = 0`
`2sin^2x = 1`
`sin^2x = 1/2`
`sinx = +-1/(sqrt2)`
`x = sin^-1(1/(sqrt2))` and `x = sin^-1(-1/(sqrt2))`
`x = 45°` and `x = -45°`