How can you put this in factored form? Can you give me step by step, as well, please?

#f(x)=x^4+9x^3+29x^2+81x+180#

1 Answer
Feb 6, 2018

#x^4+9x^3+29x^2+81x+180=color(blue)((x+4)(x+5)(x^2+9))#

Explanation:

My method of finding this was not pretty (hopefully someone else, who is more wide awake, can demonstrate a better method.

I used the Rational Factor Theorem to test a series of factors of #180# looking for a zero: #{+-1,+-2,+-3,+-4,+-5,+-6,+-9,...}#
[I actually wrote a snippet of Basic code to do this for me]
until I found #x=-4# was a zero;
this implies that #(x+4)# is a factor.

Dividing the original expression by #(x+4)# gave a quotient of #x^3+5x^2+4x+45#

I could have re-applied the Rational Factor Theorem but instead took a shot at #(x+5)# and found that it worked, giving the factoring:
#color(white)("XXX")(x+4)(x+5)(x^2+9)#
the final factor #(x^2+9)# obviously has no Real factors
so I decided this was the best I could do.