How can you simplify #1/(3sqrt(1-x^2/9))#?

1 Answer
Nov 28, 2014

note: This question comes originally from this page.

To simplify this expression I brought the #3# "inside" the radical.

#3# is equivalent to #sqrt(9)#. Thus,

1.) #1/(3sqrt(1-x^2/9))#

is equivalent to

2.) #1/(sqrt(9)*sqrt(1-x^2/9))#.

A common law of radicals is the law of "combining," which basically looks like:

#sqrt(A)*sqrt(B) = sqrt(A*B)#

where #A# and #B# can be anything.

Using this law we can simplify our expression a little further.

2.) #1/(sqrt(9)*sqrt(1-x^2/9))#

will become:

3.) #1/(sqrt(9(1-x^2/9)))#

Now, all that's left is to distribute the #9#. This gives us:

4.) #1/(sqrt(9 - x^2)#

which looks a lot less ugly than what we started with in 1 .