How do I calculate the number of moles of acetic acid present in the aliquot (25mL of a 10% vinegar solution)?

1 Answer
A08
Mar 6, 2018

Percent solutions are expressed in the form of weight/volume %, weight/weight %, or volume/volume %.

In vinegar, water is the solvent and acetic acid is the solute.

Assuming that given solution is #10%# (W/V) vinegar solution. This is #10\ g# of Acetic acid in #100\ mL# of solution.

Aliquot is #=25\ mL#
#=># There are #25/100xx10=2.5\ g# of acetic acid.

Molecular formula of acetic acid is #"CH"_3"COOH"#
Its Molar mass using average atomic masses of its constituents is #=2xx12.001+4xx1.0079+2xx15.9994#
#=60.03\ g cdotmol^-1#

#:.# Number of moles of acetic acid present in the aliquot #=2.5/60.03#

#=0.0416\ mol#

Related questions
Impact of this question
17158 views around the world
You can reuse this answer
Creative Commons License