How do I calculate this?

How do I calculate the limit of x- #sqrt(x)# where x is nearing to infinity

1 Answer
Sep 22, 2017

#lim_"x->oo" (x-sqrtx) = oo#

Explanation:

#f(x) = x-sqrtx#

#= x(1-1/sqrtx)#

#:.lim_"x->oo" f(x) = lim_"x->oo" x xx lim_"x->oo" (1-1/sqrtx)#

Now consider #lim_"x->oo" (1-1/sqrtx) = 1-0 =1#

Hence, #lim_"x->oo" f(x) = lim_"x->oo" x xx 1 = oo#