# How do I find the 7th term of a geometric sequence for which t_1 = 6 and r = 4?

${t}_{7} = 24576$
${t}_{n} = {t}_{1} \cdot {r}^{n - 1}$. So in this case you have :
${t}_{7} = {t}_{1} \cdot {r}^{6} = 6 \cdot {4}^{6} = 24576$