How do I find the area of a parallelogram on the coordinate plane? The vertices of this parallelogram are A(-4, -3) B(2, -3) C(4, -6) D(-2, -6).

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Answer 1 · 2018-04-09T04:26:30

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Area of the Parallelogram: ABCD

$Area of ABCD = B a s e \cdot H e i g h t = 6 \cdot 3 = 18 Sq.units$ $color(brown)("Area of ABCD" = Base * Height = 6*3="18 Sq.units"$

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Construct the Parallelogram ABCD on a coordinate plane

Mark the coordinates of the vertices of the parallelogram.

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As the parallelogram ABCD is on a coordinate plane, we can see that the height $D F = 3 units$ $DF= "3 units"$ .

The base $D C = 6 units$ $DC="6 units"$

Area of the Parallelogram: ABCD

$Area of ABCD = B a s e \cdot H e i g h t = 6 \cdot 3 = 18 Sq.units$ $color(brown)("Area of ABCD" = Base * Height = 6*3="18 Sq.units"$

Hope it helps.