How do I find the domain of the function #f(x)=sqrt(x+8)#?

2 Answers
Aug 17, 2017

Domain: all Real #x# such that #x>=-8#

Explanation:

The domain will be the set of #x# values that are accepted by your function (and return a value).
In this case we have to be careful because in case of a negative argument of the square root we will be in trouble.
To eliminate this possibility we say that the domain will be the set of #x# values such that the argument of the root is bigger or equal to zero (so that our function can return us a value) or:

#x+8>=0#

giving that:

#x>=-8#

So, as long as #x# remains equal or bigger than #-8# it is all right.

Aug 17, 2017

#[-8, oo)#

Explanation:

Set the expression under the square root greater or equal to zero:

#x+8 >= 0#

Solve the equation:

#x>= -8 #

Write the answer using interval notation:

#[-8, oo)#