How do I find the domain of the function #y=(1)/(sqrt(x-1))#?

1 Answer
Nov 19, 2017

#x in RR, x>1#

Explanation:

You cannot square root a negative, and you cannot divide by zero.

Other than this, this function works for all real values of x.

From this:

#x-1>0#
Because if #x=1, sqrt(x-1)=0# so we'd be dividing by a negative, which is a big no-no. Something similar goes for if #x<1#, since even #0.999-1=-0.0001<0# so we can't do this.
For any other real value, we are fine.

So the domain is:

#x in RR, x>1#