How do I find the equation of the tangent line to the curve at the given point, (2, -4)? y=4x-3x^2.

1 Answer
Mar 1, 2018

Equation of tangent line is y= -8x+12

Explanation:

Point (2,-4) , Curve: y=4x-3x^2 :. Slope of the curve

y'= 4-6x :. Slope of the curve at point (2,-4) is

m=y'=(4-6*2)=-8. Equation of tangent line in slope

point form at point (2,-4) is y+4= -8(x-2) or

y= -8x+12 [Ans]