How do I find the equation of the tangent line to the curve at the given point, (2, -4)? y=4x-3x^2.

1 Answer
Binayaka C.
Mar 1, 2018

Equation of tangent line is #y= -8x+12#

Explanation:

Point #(2,-4)# , Curve: # y=4x-3x^2 :.# Slope of the curve

# y'= 4-6x :.# Slope of the curve at point #(2,-4)# is

#m=y'=(4-6*2)=-8#. Equation of tangent line in slope

point form at point #(2,-4)# is #y+4= -8(x-2)# or

#y= -8x+12# [Ans]

Related questions
Impact of this question
3345 views around the world
You can reuse this answer
Creative Commons License