How do I find the percentage composition of Oxygen in #N_2O_5#?

2 Answers

Answer:

It is #74.1%#

Explanation:

First we find the molar mass of the entire molecule. So N is 14 and O is 16. Molar mass of #N_2O_5 = 2(14) + 5(16) =108# g/mol.

To find of the percent we take the element's mass in the molecule over the total molar mass. For #O# would be #((5*16)/108) * 100# or #100%-25.9% = 74.1% #

Feb 27, 2016

#N_2O_5# molecule contains 2 N atoms and 5 O atoms, So the molar mass of #N_2O_5# =2 x atomic mass of N +5xatomic mass of O = 2x14+5x16=108 g/mole
% of N = #2*14/108*100# =25.93
% of O =#5*16/108*100#=74.07