# How do I find the sum of the geometric sequence 3/2, 3/8?

Apparently, sum of the series is required, having infinite number of terms, unless something contrary is stated. Write the series as 3 [$\frac{1}{2} , \frac{1}{8} , \ldots$]. 1st term of the series is 1/2 and common ratio is 1/4. Formula for sum of an infinite geometric series(common ratio less than 1) is $\frac{a}{1 - r}$ = $\frac{1}{2} / \left(1 - \frac{1}{4}\right)$= $\frac{1}{2} \cdot \frac{4}{3}$ = $\frac{2}{3}$
Sum of the given series =$3 \cdot \frac{2}{3}$ =2