# How do I graph the logistic function P(t)=11.5/(1+12.8e^(-0.0266t)) on a TI-83?

Then teach the underlying concepts
Don't copy without citing sources
preview
?

#### Explanation

Explain in detail...

#### Explanation:

I want someone to double check my answer

1
Dec 25, 2016

See the Socratic graph and the explanation.
graph{x-1/.266ln((12.8y)/(11.5-y))=0 [-10, 10, -5 5]}

#### Explanation:

graph{x-1/.266ln((12.8y)/(11.5-y))=0 [-100, 100, -20, 20]}
P>0.

The inverse t-sxplicit formula

$t = \frac{1}{0.266} \ln \left(\frac{12.8 P}{11.5 - P}\right)$ is used

The P-intercept ( t = 0 ) is 11.5/13.8=0.8333, nearly.

As $t \to - \infty , P \to 0$.

As $t \to \infty , P \to 11.5$.

So, P = 11.5 is aother horizontal asymptote, besides P = 0.

The second graph is on a befitting scale to reveal this important

characteristic if this logistic function.

I hope that these data and graph will be useful.

• 7 minutes ago
• 8 minutes ago
• 9 minutes ago
• 11 minutes ago
• 55 seconds ago
• A minute ago
• 3 minutes ago
• 3 minutes ago
• 6 minutes ago
• 7 minutes ago
• 7 minutes ago
• 8 minutes ago
• 9 minutes ago
• 11 minutes ago