How do I graph #y=cos(x-π/4)#?

1 Answer
May 7, 2018

Answer:

Below

Explanation:

#y=cos(x-pi/4)# is in the general form #y=acos(nx-b)#
where:
a = amplitude

So we know that its amplitude is 1
the period is: #T=(2pi)/n = (2pi)/1 = 2pi#
and we shift the equation to the right by #pi/4# from #y=cosx#

Below is the graph #y=cosx#
graph{cosx [-10, 10, -5, 5]}

Now, this equation needs to be shifted to the right by #pi/4# which means that each x-value needs to have #pi/4# added to it. Just to be clear, the y-value still remains the same

Below is the graph #y=cos(x-pi/4)#

graph{cos (x-pi/4) [-10, 10, -5, 5]}