How do I prove that 4sin(62.5˚+x/2)*cos(27.5˚-x/2) is the same as 4sin^2(x/2+62.5˚)?

1 Answer
Jun 4, 2018

4sin(62.5˚+x/2)*cos(27.5˚-x/2)

=4sin(62.5˚+x/2)*sin(90^@-(27.5˚-x/2))

=4sin(62.5˚+x/2)*sin(62.5˚+x/2))

=4sin^2(62.5˚+x/2)